DISQUS

tin2 · 1 year ago

better luck next time

janak_kumar · 10 months ago

i want many type of for loop code

seema · 7 months ago

good

Peter · 5 months ago

concerning i < array.length: if you really want to run through each array item, you need to initialize i with 0:
for (int i = 0; i < array.length; i++) {
System.out.println(array[i]);
}

Gobitha · 5 months ago

please give appropriate generic syntax form to this for loop
"for(int i:arr){System.out.println(i);}"

donatjava · 4 months ago

simpl program for loop

fiaeriza · 3 months ago

how to do the program and output like this:
#######
######
#####
######
#####
###
##
#

usernamer · 2 months ago

please fix it for me!

/**
* @(#)hehe.java
*
*
* @author
* @version 1.00 2009/10/7
*/

import java.io.*;
public class hehe{

public static void main(String args[]) throws IOException {

BufferedReader input = new BufferedReader(new InputStreamReader(System.in));

int user;
int pass;
int i=1;
String yesno;
char yorn;



while(i<=3){
System.out.print("Enter Username:");
user=Integer.parseInt(input.readLine());
System.out.print("Enter Password:");
pass=Integer.parseInt(input.readLine());
for(int j=0;j<=5;j++){
System.out.println();
}
System.out.println();
if((user==2009)&&(pass==2010)){
System.out.println("ACCESS GRANTED!");
for(int j=0;j<=5;j++){
System.out.println();
}
System.out.println();


}else
{
System.out.println("=ACCESS DENIED=");
System.out.println("Please Try Again");
for(int j=0;j<=5;j++){
System.out.println();
}
}
i++;






String choice;

System.out.println("Choices:");
System.out.println("A.PURCHASING ITEMS");
System.out.println("B.EXIT");
System.out.print("Enter Your Choice: ");
choice=input.readLine();
if (choice.equals("A"))
{






}else if(choice.equals("B"))

{
System.out.println("Do you really want to exit?");
System.out.println("Yes(Y)No(N)");
yesno=input.readLine();
}




}

}
}

diamishra · 4 weeks ago

the description is not very good